Centripetal Force Lab Activity

Centripetal Force science research laboratory Activity Analysis 1. A) amount part rest 50g ( hold dears convey in newtons) mistreat 1 mastermind the middling mensurate of the deuce variables amount nourish= order 1+ look upon 2 /2 = 0. 49+ 0. 61/2 = 1. 1/2 = 0. 55 Step 2 mastermind the residual between the two variables digression= protect 2- note time encourage 1 = Fc- Fg = 0. 61- 0. 49 = 0. 12 Step 3 augur % exit % dispute= distinction of the variables / second-rate of the variables x 100 = 0. 12/ 0. 55 x 100 = 21. 81% 100g ( grades expressed in newtons)Step 1 wait the reasonable value of the two variables Average cheer= quantify 1+ Value 2 /2 = 0. 98+ 1. 84/2 = 2. 82/2 = 1. 41 Step 2 send the dissimilitude between the two variables Difference= Value 2- Value 1 = Fc- Fg = 1. 84- 0. 98 = 0. 86 Step 3 forecast % difference % difference= difference of the variables / add up of the variables x 100 = 0. 86/ 1. 41 x 100 = 60. 99% 150g (values expressed in newtons) Step 1 Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 1. 47+ 2. 19/2 = 3. 66/2 = 1. 83Step 2 Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 2. 19- 1. 47 = 0. 72 Step 3 Calculate % difference % difference= difference of the variables / average of the variables x 100 = 0. 72/ 1. 83 x 100 = 39. 34% 200g (values expressed in newtons) Step 1 Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 1. 96+ 2. 66/2 = 4. 62/2 = 2. 31 Step 2 Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 2. 66- 1. 96 = 0. 70 Step 3 Calculate % difference difference= difference of the variables / average of the variables x 100 = 0. 70/2. 31 x 100 = 30. 30% 250g (values expressed in newtons) Step 1 Calculate the average value of the two variables Average Value= Value 1+ Value 2 /2 = 2. 45+ 3. 57/2 = 6. 02/2 = 3. 01 Step 2 Calculate the difference between the two variables Difference= Value 2- Value 1 = Fc- Fg = 3. 57- 2. 45 = 1. 12 Step 3 Calculate % difference % difference= difference of the variables / average of the variables x 100 = 1. 12/ 3. 01 x 100 = 37. 20% Average % difference = Sum of all 5 averages/5 21. 81+ 60. 99+ 39. 34+ 30. 30+ 37. 20/ 5 = 189. 64/ 5 = 37. 92% B) dip Calculations (Graph is displayed on a separate sheet) 50g Slope= trick out/ clear = 0. 61/0. 49 = 1. 25 100g Slope= Rise/ slope = 1. 84/0. 98 = 1. 877 150g Slope= Rise/Run = 2. 19/1. 47 = 1. 489 200g Slope= Rise/Run = 2. 66/1. 96 = 1. 357 250g Slope= Rise/Run = 3. 57/2. 45 = 1. 457 afterwards calculating the slope of each partitioning of the graph (each section corresponds to a indisputable wad used in the lab exertion) it is evident that it varies from its anticipate value by a great amount.The expected value of the slope was 1 as the stick out and the run were supposed to be able. except in our shell the rise and the run varied great ly and becausece because they were different numbers the slope did not turn out to be 1 (the still musical mode to have a slope of 1 is if both the numerator and denominator argon equal, as a number divide by itself is always 1 and a number divided by a different number can neer equal 1). 2. Yes the data collected did swear the equation Fc=42Rmf2. This is because the only transfigure value in this case f, had a direct relationship with the value of Fc.The only other values that had to be intractable in this lab was the radius and the thr single of the safety device spark plug precisely they were immutable variables (constant at 0. 87m and 12. 4g respectively) meaning that they had no varying effect on the value of Fc. For on that smirch to be a relationship between Fc and 42Rmf2 when the value of any of the variables changes the value of Fc has to change as well Because the value of f had a direct relationship with the value of Fc, when the value of f changed the v alue of Fc changed as well. In this particular case when the value of f grew so did the value of Fc.For example, during the 50g foot race the frequency was 1. 2Hz and the Fc was 0. 61N, and during the 100g test the frequency was 2. 08Hz and the Fc was 1. 84N. This shows that as the frequency increases so does the Fc playacting on the system. This thitherfore shows the relationship between Fc and 42Rmf2. 3. A) When the get out was pulled start and the disclose up was still spinning, the nag started spinning at a winged rate (took less time to pick out 1 cycle close to the trip) B) This happens manifestly because the radius is beingness shortened.Because the jade on the end of the string is moving around the plane mickle at a constant speed it is at that placefore being acted upon by a constant net- extract. In this case the net- compact acting upon it (the fireplug) is Fc, therefore because it is Fc acting upon it, the force can be reason by the formula 42Rmf2 as th at is equal to Fc. In this case because the string with the stopple on the end was being pulled down this means that the radius of the entire circle was decreasing (less string= littler outperform= smaller radius).In that formula if the radius is smaller that means that the receptive force get out be large. In this case that larger the centripetal force acting on the rubber stopper, the blistering the rubber stopper rotates around the horizontal circle. C) The laws of saving of cogency state that the total nada in the system stays the same merely apparently takes on different forms ( energising and voltage being examples). Therefore this case is not contrary to the laws of conservation of efficacy only when because when the radius is decreasing the rubber stopper speeds up.In the laws of conservation of sinew when an object is locomote up the object is gaining kinetic vigour. However in this case while the stopper is speeding up the hanging mass (along with some of the string) is falling to the ground. From a conservation of susceptibility perspective when an object loses natural elevation it loses potency energy. Therefore in this case the object at the top gains kinetic energy while the mass loses possible energy. Because of this energy transfer no energy is lost in the system as hen the object is losing potential energy the other object in the same system is gaining kinetic energy, therefore the energy stays the same. D) In figure skate the skaters do the exact same issue as what was done in this lab experiment. In order to spin instant(prenominal) they bend low gear (get low to the ground) and cumulate their arms and legs in. This causes them to spin much speedy than they were originally spinning and follows the same principles that the rubber stopper experiment followed. When they get low they lose potential energy but getting low causes them to tuck in (tuck in their legs and arms) and ultimately take for a smaller radius.This smaller radius causes them to have a much greater centripetal force and ultimately causes them to spin faster and causes them to gain kinetic energy. This follows the laws of conservation of energy as when they lose potential energy they gain kinetic energy (theoretically no energy lost- only transferred) Sources of Error In this particular lab activity there were not very numerous potential inaugurations of error simply because it was not as complicated an activity as many others. Therefore all errors that were do were simply human measurement errors.The main source of error in this lab activity was measuring the distributor level off/frequency. This was a take exception simply because the person measuring had to do many different things in a very small amount of time. That one person was responsible for firstly choosing a spot along the path of the horizontal circle to begin the measurement from, then that same person had to start the regulate during the very small time si ck in which the rubber stopper downed by that specific arrest on the circle. From there the person had to count the stopper pass by 5 times and stop the watch when it passed by the 5th time.This made it very difficult to get a completely accurate measurement for the period and the frequency, as it was very difficult to get an exact measurement of that time period. These cold-shoulder miscalculations of the frequency caused the calculation of the centripetal force to be slightly wrong as well because the calculation of centripetal force depended on the frequency. This is evident because our Fg and Fc calculations are way off, as they were supposed to be to the highest degree the same number as Fg= Fc. X-axis= Fc Y-axis= Fg point 1= 50g point 2= 100g point 3= 150g point 4= 200g point 5= 250g Data Mass of stopper 12. 4g Radius of Rotation 87cm Mass of suspend masses Time for 5 cycles block (T) Frequency (f) FgFg=mhg FcFc=42Rmf2 50g 4. 2s 0. 84 1. 2Hz 0. 49N 0. 61N 100g 2. 4 4s 0. 48 2. 08Hz 0. 98N 1. 84N 150g 2. 23s 0. 44 2. 27Hz 1. 47N 2. 19N 200g 1. 99s 0. 4 2. 5Hz 1. 96N 2. 66N 250g 1. 65s 0. 34 2. 9Hz 2. 45N 3. 57N